Analog Electronics
OP-AMP and its Applications
Practice questions from OP-AMP and its Applications.
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IncorrectWhich of the following statements is/are TRUE with respect to an ideal opamp?
Following are properties of ideal op-amp:
1. Infinite open-loop differential gain
2. Infinite input Impedance
3. Zero output Impedance
4. Zero open-loop common-mode gain
Thus, from given options (a) and (c) are correct.
All the components in the bandpass filter given below are ideal. The lower -3 dB frequency of the filter is 1 MHz.
The upper -3 dB frequency (in MHz, rounded off to the nearest integer) is _________.
A 4-bit weighted-resistor DAC with inputs , and (MSB to LSB) is designed using an ideal opamp, as shown below. The switches are closed when the corresponding input bits are logic ' 1 ' and open otherwise.
When the input changes from 1110 to 1101, the magnitude of the change in the output voltage , rounded off to the nearest integer) is ___________ .
Given op-amp circuit is inverting summing amplifier
for
For
The opamps in the circuit shown are ideal, but have saturation voltages of .
Assume that the initial inductor current is . The input voltage is a triangular signal with peak voltages of and time period of . Which one of the following statements is true?
is delayed by relative to , and is a triangular waveform.
is not delayed relative to , and is a trapezoidal waveform.
is not delayed relative to , and is a triangular waveform.
is delayed by relative to , and is a trapezoidal waveform.
OPA1non-inverting Schmitt trigger
By Voltage Division Rule,
At UTP and LTP, Inverting and Non-Inverting Terminals would have equal voltage
For
Hence, we can draw wave form like,
Hence, is delayed las w.r.t .
Only from here we can say option (d) is correct. But to complete analysis
Now, for OPA2,
As is a square wave, we can take it as constant in each period.
Initially .
If we take in ,
Now, if
Then,
Hence,
Now, at
Now, if
From to , is fixed
Hence, we get a trapezoidal waveform in steady state.
The of the circuit shown below is
Given circuit
Here, is an inverting amplifier and is a noninverting amplifier.
For , applying KCL at (-)ve node
