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Q#1
Network Basics
GATE EE 2017
MCQ
+2 marks
-0.66 marks
For the network given in figure below, the Thevenin’s voltage Vab is
– 1.5 V
– 0.5 V
0.5 V
1.5 V
Explanation:
Apply Source Transformation,
Apply KVL in first loop
Apply KVL in second loop
Solving (i) and (ii) I1 = 1.9A, I2 = 1.75A
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