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Q#1 Sinusoidal Steady State Analysis GATE EE 2004 MCQ +1 mark -0.33 marks

In the figure the value of Z in Figure, which is most appropriate to cause parallel resonance at 500 Hz, is

Q1.jpg

125.00 mH

304.20 µF

2.0µF

0.05µF

Explanation:

For parallel resonance to be happen, imaginary part of admittance of parallel network should be zero.

Since inductor is already exists. So, Z should be capacitive

Admittance of parallel network, Y=

=

For imaginary part of admittance of zero

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