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Q#1 Network Theorems (DC Circuits) GATE EE 2014 NAT +2 marks -0 marks

The Norton’s equivalent source in amperes as seen into the terminals X and Y is__________.

C:\Users\Ankit\Dropbox\GATE papers\EE papers\Typed\Gate-EE-2014\Gate-EE-2014_3\EE03_2014 images\18.jpg

Explanation:

To determine Norton’s Current, short circuit the XY terminals

C:\Users\Ankit\Dropbox\GATE papers\EE papers\Solutions\network\14,15,16 Images\29.jpg

Using Mesh analysis,

For first loop:        

 

2.5 = 5  – 2.5    ……………..(1)  

For second loop:        

2.5 = 7.5  – 5     …………….(2)

Adding (1) & (2),

5 = 5 

 = 1A and ISC=1A

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Network Analysis 208 0 0
Signals and Systems 21 0 0
Control Systems 18 0 0
Analog Electronics 10 0 0
Digital Electronics 138 0 0
Electrical Machines 17 0 0
Power Electronics 17 0 0
Power Systems 18 0 0
EMFT EE 8 0 0
Measurement 6 0 0
Engineering Mathematics 27 0 0
General Aptitude 104 0 0