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Q#1 Sinusoidal Steady State Analysis GATE EE 2014 MCQ +2 marks -0.66 marks

The voltage across the capacitor, as shown in the figure, is expressed as +

10.jpg

The values of and  respectively, are

2.0 and 1.98

2.0 and 4.20

2.5 and 3.50

5.0 and 6.40

Explanation:

Using super position theorem,

C:\Users\Ankit\Dropbox\GATE papers\EE papers\Solutions\network\14,15,16 Images\10_1.jpg

First, open circuit current source

By Potential Division,

 =   =

Therefore,  ;  

Now, short circuit voltage source

C:\Users\Ankit\Dropbox\GATE papers\EE papers\Solutions\network\14,15,16 Images\10_2.jpg

 

By Current Division,

 

Hence, =1.98 , = 78.69°

Thus, the capacitor voltage is given by,  

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